Question

What is the remainder when (2x4 – 3x3 + x2 – 3x – 3) ÷ (x – 2)

Answer 1

Start with

Answer 2

Or you could use
f(x)=2x4 – 3x3 + x2 – 3x – 3,
When (x-2)=0,
x=2

Then
f(2)=2(2)4 – 3(2)3 + (2)2 – 3(2) – 3=?

Answer 3

-9

Answer 4

Careful
\[2(2)^4 – 3(2)^3 + (2)^2 – 3(2) – 3=?\]

Answer 5

@.Sam. 6

Answer 6

Nope

Answer 7

@.Sam. well idk

Answer 8

\[2^4=2\times 2 \times 2 \times 2=16\]
\[2^3=2 \times 2 \times 2 = 8\]
\[2^2=2 \times 2 = 4\]
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So,
\[2(2)^4–3(2)^3+(2)^2–3(2)–3 \\ 2(16)-3(8)+4-6-3 \\ =3\]