Question

Triangle A B C is shown with horizontal base B C 8 feet, one vertical side C A 6 feet, and the remaining side A B an unknown number of feet, indicated with a question mark. Triangle J K L is similar to triangle A B C. Side K L corresponds to B C and is twelve feet long. Side J L corresponds to A C and is 9 feet long. Side J K corresponds to A B and is fifteen feet long.

What is the length of side A B?

Answer 1

Where is triangle ABC and JKL ?? @twilaswift

Answer 2

always remember that in similar triangles we have,
\[\huge \bf \frac{AC}{JL}=\frac{BC}{KL}=\frac{AB}{JK}\]

Answer 3

Okay... this is the answers I have:

10 feet
11 feet
12 feet
13 feet
I think it's 12 feet.

Answer 4

\[\huge \bf \frac{6}{9}=\frac{8}{12}=\frac{AB}{15}\]

Answer 5

solve for AB? @twilaswift

Answer 6

13.

Answer 7

No wait it's 11.

Answer 8

\[\huge \bf \frac{6}{9}=\frac{2}{3}\]
so,
\[\huge \bf \frac{2}{3}=\frac{AB}{15}\]

so solve for x?

Answer 9

@twilaswift

Answer 10

12

Answer 11

do cross multiply,
we get
\[\huge \bf 15 \times 2=AB \times 3\]
divide 3 from both the sides, we get
\[\huge \bf AB=\frac{15 \times 2}{3}\]

Answer 12

can you solve it? @twilaswift

Answer 13

30?

Answer 14

But my answers are only 10, 11, 12 and 13 no 30.

Answer 15

\[\huge \bf 15 \times 2=30\]
then divide 30 by 3

Answer 16

so what is our answer? @twi

Answer 17

@twilaswift