Question

One of the fastest recorded pitches in the mlb was 101.0 mi/h. If a pitch was thrown horizontally with this velocity, how far would the ball fall by the time it reached home plate 60.5 ft away

Answer 1

Use the kinematic equation in the x direction, knowing that acceleration is 0 in the x direction. Use it to find time. Then plug that time into the same kinematic equation, but in the y-direction. You should get the answer. Equation: x = xnaught + vnaught*t

Answer 2

@alffer1 what about effect of gravity?
If gravity is considered then it will be projectile motion-first calculate the time taken (T) by the ball to reach plate
s=ut+1/2gt^2
then find s for t=2T

Answer 3

given that i got the answer of .277 feet

Answer 4

That's what I meant. Gravity does not affect anything in the x-direction. Find the time in the x direction. Then plug that time and the constant g for acceleration in the y direction. There is no acceleration in the x direction, but there is an acceleration of 9.8 in the y direction. @redeye: did you take into account g?

Answer 5

yes i did

Answer 6

.277 doesn't seem reasonable. Double check. i'll try it too. delta y = vnaught*t + (1/2)g t^2

Answer 7

Make sure all units are in ft and seconds. I got a drop of .818 ft (sig figs).