Question

help please work attached

Answer 1

what is the perfect square for #1

Answer 2

isnt the answers in the question??

Answer 3

idk

Answer 4

i only need hepl with 1,2,3,5,4,6 and 8

Answer 5

5.
\[\frac{ \sqrt[3]{625} }{ \sqrt[3]{25} }=\frac{ \left( 625 \right) ^{\frac{ 1 }{ 3 }}}{\left( 25 \right)^{\frac{ 1 }{ 3 }} }\]
\[=\frac{ \left( 5*5*5*5 \right)^{\frac{ 1 }{3 }} }{\left( 5*5 \right)^{\frac{ 1 }{ 3 }} }\]
\[=\frac{ \left\{ \left( 5 \right)^{4} \right\}^{\frac{ 1 }{ 3 }} }{\left\{ \left( 5 \right)^{2} \right\}^{\frac{ 1 }{3 }} }\]
\[=5^{\frac{ 4 }{ 3 }}*5^{\frac{ -2 }{3 }}=5^{\frac{ 4-2 }{ 3 }}=\left( 5^{2} \right)^{\frac{ 1 }{ 3 }}\]
\[=25^{\frac{ 1 }{ 3 }}=\sqrt[3]{25}\]
i have solved 5th you can try others also

Answer 6

i tried the others but i didnt get them right

Answer 7

1.
\[5\sqrt{63}=5*\sqrt{3*3*7}=5*\sqrt{3^{2}*7}\]
\[=5*3\sqrt{7}=15\sqrt{7}\]

Answer 8

2.
\[\sqrt[4]{16x ^{5}y ^{4}}=\left\{ \left( 2 \right)^{4}x^{4} *x*y ^{4}\right\}^{\frac{ 1 }{ 4 }}\]
\[=\left\{ \left( 2xy \right)^{4}x \right\}^{\frac{ 1 }{ 4 }}=\left( 2xy \right)^{4*\frac{ 1 }{ 4 }} x ^{\frac{ 1 }{ 4 }}\]
\[=2xy \sqrt[4]{x}\]

Answer 9

3.
\[\sqrt{\frac{ 7 }{ 8y }*\frac{ 2y }{ 2y }}=\sqrt{\frac{ 14y }{ 16y ^{2} }}=\sqrt{\frac{ 14y }{ \left( 4y \right)^{2} }}\]
\[=\frac{ \sqrt{14y} }{4y }\]

Answer 10

\[\left( -2\sqrt{15} \right)\left( 4\sqrt{21} \right)=-2*4\sqrt{15*21}\]
sOLVE IT

Answer 11

6.\[\sqrt{12}+\sqrt{48}-\sqrt{27}=\sqrt{2^{2}*3}+\sqrt{2^{4}*3}-\sqrt{3^{2}*3}\]
\[=2\sqrt{3}+4\sqrt{3}-3\sqrt{3}=\left( 2+4-3 \right)\sqrt{3}=3\sqrt{3}\]

Answer 12

\[\frac{ 6 }{ 5+\sqrt{3} },rationalise \it.\]
\[multiply the numerator and denominator by 5-\sqrt{3}\]
\[\frac{ 6 }{ 5+\sqrt{3} }-\frac{ 5-\sqrt{3} }{ 5-\sqrt{3} }=\frac{ 6\left( 5- \left( \sqrt{3} \right) \right) }{ 25-3 }\]
and get the answer.

Answer 13

correction in last
on left hand side write *in place of -

Answer 14

\[i.e.,\frac{ 6 }{ 5+\sqrt{3} }*\frac{ 5-\sqrt{3} }{5-\sqrt{3} }=\]

Answer 15

correction again write
sqrt{6}in place of 6

Answer 16

if you can't solve then write me.