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Mathematics 11 Online
OpenStudy (anonymous):

can someone help me out with the circle formula?

OpenStudy (anonymous):

I dont understand

OpenStudy (anonymous):

Circle formula for what? Circumference?

OpenStudy (anonymous):

(x-g)+(y-h)

OpenStudy (anonymous):

the one to find the radius

OpenStudy (anonymous):

Well wait, is this circumference or not? Because I know other formulas and I don't want to give you the wrong one, you know?

OpenStudy (anonymous):

(x-g)^2+(y-h)^2=R^2

OpenStudy (anonymous):

i dont know what its called

OpenStudy (anonymous):

The formula need some modifications: (x-h)² + (y-k)² = r² Note that each term on the left is squared and the term on the right is squared. If your equation fits this format (where h, k, and r are constants. then you have a circle whose center is (h, k) and whose radius is r. The radius is the R to the second power of. Either i'm confused on what you're asking, or i dont know dude.

OpenStudy (anonymous):

I dont know how to apply it to circles. Like have a circle and its asking me to use the formula

OpenStudy (anonymous):

OH umm

OpenStudy (anonymous):

Here. circles (h,k) is the center of the circle and r is the radius of the circle. just apply the values in the formula u can find the radius square and find the root value you will get the radius.

OpenStudy (anonymous):

then what are the x and y for?

OpenStudy (anonymous):

I honestly am not good at this, but I THINK you just put the other numbers into X & Y, You can try asking someone else in the side chat or something. Dude sorry, but I hope I helped you. Good luck! If you need any more help, i'll be here!! You can try looking this up on google, or go on yahoo answers.

OpenStudy (anonymous):

what if the the center of my circle is the origin?

OpenStudy (jdoe0001):

\(\bf (x-5)^2+(y-7)^2 = 16 \implies (x-\color{red}{5})^2+(y-\color{red}{7})^2 = 4^2\\ (\color{red}{5}, \color{red}{7}) \Leftarrow center, radius \implies 4\\ \textit{if the center of the circle is the origin (0,0}\\ (x-0)^2+(y-0)^2 = r^2 \implies x^2+y^2 = r^2\)

OpenStudy (anonymous):

alright thank you soo much! :D

OpenStudy (jdoe0001):

yw

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