Question

please help just a few questions.

Answer 1

whats the question?

Answer 2

Choose the correct simplification of 7 over x to the power of negative 2.

x to the 2nd power over 7

7x2

7 over x to the 2nd power

Already simplified

Answer 3

\[Given: \frac{ 7 }{ x ^{-2} }\]
\[Choices: \frac{ x^2}{ 7 } or 7x^2 or \frac{ 7 }{ x^2 } \]
or already simplified

When you have a negative power you can flip it to the opposite side of the fraction and make it positive. So which choice would that be?

Answer 4

Not quite you only want to flip the part that has the negative power on it. The 7 does not have a negative power on it so it would stay put.

Answer 5

Also not right, let me try to explain a little more. Negative exponents are like dividing so \[x^{-2}\] is like saying \[\frac{ 1 }{ x*x }\]

So in this case you have \[\frac{ 7 }{ \frac{ 1 }{ x*x }}\]

To kind of expand it again you can also say you have:
\[\frac{ \frac{ 7 }{ 1 } }{ \frac{ 1 }{ x*x } }\]

So you are dividing two fractions to divide to fraction you simply flip the bottom one and multiply them.
\[\frac{ 7 }{1} * \frac{ x*x }{ 1 }\]

The ones just disappear and you get:
\[7*x*x\]

Answer 6

Well let me show you something neat.\[\frac{1}{x^{-a}} = x^{a}\]

Answer 7

so b