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Prove or disprove: Every symmetric and transitive relation on a nonempty set is an equivalence relation.
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I believe it should be disproved but I'm having difficulty figuring out a relation on a set A
So say A={a,b,c,d}.
find a relation that is symmetric and transitive, but not reflexive
R={(a,b),(b,a),(b,c),(a,c)}
that's easy it seems but I wonder if I am forgetting something.
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i am not sure that one is symmetric
(c,a)
(c,b)
you have (b,c) but not (c, b(
it needs (c,b) too
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I mean (c,a)
right?
lets try this
on the set \(\{a, b, c, \}\) define the relation \(\{(a,a), (a, b), (b, a), (b,b)\}\) think you will see that it is symmetric and transitive, but not reflexive it may seem like cheating, but it is not
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