if m men can paint a house in d days, how many days will it take m+2 men to paint the same house?
\[A) D+2\] \[B) D-2\] \[C) \frac{ M+2 }{ MD }\] \[D) \frac{ MD }{ M+2 }\] \[E) \frac{ MD+2D}{M }\]
So you have to make a ratio between the amount of men and the amount of days spent, can you do that?
uhhh m:d and m+2:d+2 ?
Nope, sorry not that simple you have We don't know big D so pretend there is a divided sign over the m and m+2 and d and D m = d m+2 = D
Then you have to solve for D
how you do that id d=m+2?
unless you mean substitute m for d? so d+2=D ?
You have a ratio of m : m+2 and you are trying to find how much D is in terms of d. which is not always the same ratio. So you have to make an equation out of it and solve for a unknown. D
The equation I made was m/(m+2) = d/D Then you just have to solve for D
then i got \[(D)\frac{ m }{ m+2 }=\frac{ d }{ D }(D)\] then \[(D)\frac{ m+2 }{ m}=d\] now what?
umm i meant \[(D)\frac{ M}{m+c }=d\]
Now you multiply by m+2 and divide by m.
so like \[D=\frac{ d(m+c) }{ m }\rightarrow D=\frac{ dm+dc }{ m } \]?
Yup! except the c is supposed to be a 2.
uhh replace c with 2 my retardedness happend
lol
We all do it :x
thank you!!!
Your welcome!
i got more question..wanna answer em? :3
I can go for one more. Then I gotta sleep.
thanks i owe you one....sorry for the crappy internet there is enough food at a picnic to feed 20 adults or 32 children.If there are 15 adults at the picnic, how many children can still be fed? A)6 B)8 C)12 D)16 E)18
So can you make the equation?
well i got 20a=32c 15a+xc
Remember in ratios you have to keep all of the a's and c's on one side of the equation while making it.
So you need to do total adults / adults there = total children / children there
oh.... so like \[\frac{ 20 }{ 15 } = \frac{ 32 }{ x }\]
Yup, now you just solve for x :)
x=24 ?
Yup it does!
ok... so whats next?
Well x was the coefficient of your children there, so you can have 24 children with 15 adults there.
oh so like 24 children=15 adult so you can do 32-24=8 so you can have 8childrens?
Erm... Well no, but if 24 isn't the right answer, then I don't know what is because if you take the ratio of total children to total adults you get a ratio of 32/20 and that is 1.6 so if you multiply that by the 15 adults that are there then you get 24 also. Just doing the same thing a different way and still getting the same answer... I really don't know. I'm sorry.
oh ok its ok :)
well good night :)
Good night
@ineedhelpnow08, your original question involves inverse proportions
\[\frac{MD + 2D}{M}\] is not the correct answer. I can demonstrate why.
Let's assume it takes 5 men 2 days to paint a house. How many days would it take 7 men to paint the house?
Let's set it up in a way similar to @Arfney's setup: \[\frac{5 \space\text{men}}{7\space\text{men}} = \frac{2 \space\text{days}}{x \space\text{days}}\] If we solve for x, then it should be less than 2 since we have more men working: \[\frac{5}{7} = \frac{2}{x}\] \[5x = 14\] \[x = \frac{14}{5}\] \[x \approx 2.8\] This cannot be correct, because this would mean that with 7 men it would take longer to paint a house than with 5 men.
The correct approach is to understand that we're dealing with inverse proportions. We know it is inverse proportions because with MORE men, it should take LESS days. In other words, if the number of men INCREASE, then the number of days DECREASES. So...how shall we proceed? By simply using the formula for inverse proportion: xy = k When we have inverse proportions, we are usually dealing with two separate cases. Such is true for this problem: In the first case, x = m, y = d...so md = k In the second case, x = m + 2, y = D, so: (m + 2)(D) = k So putting the two together we have: md = k (m + 2)(D) = k and k is the constant of variation so it is the same for both cases therefore, set k = k: k = k md = (m + 2)(D) Now, we can solve for D: \[\frac{md}{m + 2} = D\] Which is equivalent to one of your given answer choices. To test to make sure it is correct, lets go back to the sample problem. We understand that it needs to take 7 men LESS than 2 days to paint the house, so lets input the numbers and see if our equation holds true: m = 5 d = 2 m + 2 = 7 \[\frac{(5)(2)}{7} = \frac{10}{7} = \frac{7 + 3}{7} = \frac{7}{7} + \frac{3}{7} = 1 + \frac{3}{7} = 1 \frac{3}{7}\] \(\large 1 \frac{3}{7} < 2\) So we know our equation is correct :)
thanks..... but too late already hand in the homework :I
I know...I figured that may have happened. Sorry about that.
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