Help please! Please please please!(: With the problem below, Determine the following: g(2)=____ g(4)=____ absolute max of g(x) is when x is ____ and is the value ____.
Let: \[f(x)=0 , x<4 \] \[f(x)=5 , -4\le x <1\] \[f(x)=-2 , 1\le x <3\] \[f(x)=0 , x \ge3\] and \[g(x)=\int\limits_{-4}^{x} f(t) dt\]
really would help to draw a picture, which is just a bunch of horizontal lines
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the integral is the area of the rectangle so \[\int_{-4}^1f(x)dx=4\times 5=20\] which is the largest it can be, because the stuff after than it negative (below the \(x\) axis)
To find the extrema of \(g(x)\), apply the first derivative test. If \(\displaystyle g(x)=\int_{-4}^xf(t)~dt\), then \(g'(x)=f(x)\). Find your critical points (i.e. when \(f(x)=0\)), which shouldn't be too hard, then determine the intervals on which \(g\) is increasing/decreasing.
therefore the max is \(20\) when \(x=1\)
this max is not 20
hmm i think the critical points are not where the derivative is 0, but rather where the derivative is undefined small matter though
oh of course, sorry, the max is \(5\times 5=25\) my mistake
@satellite73, both, actually: http://en.wikipedia.org/wiki/Critical_point_(mathematics) (first sentence)
@SithsAndGiggles i mean in this example
Right, I was thinking more generally :P
I'm so confused. so how is it determined at g(2) and g(4)?
in general of course critical point is where derivative is zero or undefined in this example the important critical point would be at the change in the definition of the function, where the derivative would not be defined
take the area of the rectangle at \[g(2)=\int_{-4}^2f(x)dx\] you have \(25\) for the area of the rectangle with base 5 and height 5, then \(-2\) for the area of the rectangle with base 1 and "height" \(-2\)
therefore \(g(2)=23\)
so with that g(4)=21 right?
sorry i got closed out
yea, \(g(4)=21\) right
yay! thanks!!(:
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