4x^2-10x-6
do you want to solve the quadratic equation: \[4x^{2}-10x-6=0\] or what?
I need to factor it.
ok then...lets see \[4x^{2}-10x-6=0\] can you write the term -10x as the sum/difference of two terms whose product is: \[(-6)(4x^{2})=-24x^{2}\]?
-12x +2 ?
*-12x + 2x
yea right
so we can write \[4x^{2}-10x-6=4x^{2}-12x+2x-6\] right?
Yep
now do you see some common factor between first two terms?between \[4x^{2} and 12x\]
2
4
anything more?greatest common factor?
1,2, and 4 are the only things that go into 4
Hint: \[4x^{2}=4*x*x\] and \[12x=4*3*x\] they have 4x common factor..don't they?
yes
similarly...what is the greatest common factor between \[2x \] and 6?
@staldk3 it can be solved by factorization and quadratic formula also.
2
Since 2 has an x and 6 doesn't.
yea right..can we right \[4x^{2}-12x+2x-6=4x[x-3]+2[x-3]\] ?
write*
Yes.
What about 2(2x+1) (x-3) ?
yea that's it
4x^2-10x-6 4x^2-4x-6x-6=0 4x(x-1)-6(x-1)=0 (4x-6)(x-1)=0 (4x-6)=0 , (x-1)=0 4x=6 , x=1 x=6/4 , x=3/2 ,
@Imtiaz7 how can you write \[-10x\] as \[ -6x-4x \] while the product of -6x and -4x isn't \[-24x^{2}\]?
Moreover..Please help the user find the answer..don't give the whole solution, start with a few hints, that'd be more appreciated.
@stgreen it is a rule in factorization that (not write just consider) multiply the first number(4) to last (6) then it become 24 now second point is take two numbers between last and first number which is the sum of middle number and if we multiply it then it become 24
you forgot to consider signs
yes you are right @stgreen
um... 2(2x +1) (x-3) was the final answer right?
yup
thanks for the help
Join our real-time social learning platform and learn together with your friends!