Question

x^1/2 +sqrt3x^1/4 -18
then,
(x^1/4)^2 +sqrt3x^1/4 -18
then you factor,
((x^1/4)+ or - ?) repeat.
How do you factor 18 to also when equal the sqrt3x

Answer 1

it doesn't...with an irrational coefficient you have to use quadratic formula

Answer 2

I'd copy and paste the quadratic formula of this that I posted on your previous question, but not sure how O.o

Answer 3

you can...highlight the latex, then right click, select maText i think .... then it opens in text format so you can copy it

Answer 4

\[\frac{ -(3^{\frac{ 1 }{ 4 }})\pm \sqrt{(3^{\frac{ 1 }{ 4 }})^{2}-4(-18)} }{ 2 }\]

Answer 5

Oh, cool :D

Answer 6

so for inside the sqrt i got 30.9375, what next

Answer 7

Not sure how you got that inside of the square root O.o But since all of this is calculator work really anyway. When you do the whole thing, you get the answers 3.64 for the + part of it and -4.95 for the - part of it. So then you have this:
\[x ^{\frac{ 1 }{ 4 }} = 3.64\]
\[x ^{\frac{ 1 }{ 4 }}= -4.95\]
Now ya just solve for x

Answer 8

solve for x how?

Answer 9

Since x is to the 1/4 power, you would need to raise your answers to the 4th power.

Answer 10

Now what I should definitely point out is that when you take an even root of something, you cannot end up with a negative answer. So there is no possible way for x^(1/4) to = -4.95 or negative anything. So your one answer will be (3.64)^4

Answer 11

\[x ^\frac{ 1 }{ 2 } -5\sqrt{3}x ^\frac{ 1 }{ 4 } +18\]

Answer 12

they changed the problem on me for taking too long

Answer 13

Ah. Well, we had the last problem done anyway, so this problem is the same thing anyway :/ gimme a sec for calculator magic, haha x_x

Answer 14

great ! cause i dont have one

Answer 15

So wait, is the 3 also to the 1/4 power or only square root?

Answer 16

just how its written

Answer 17

Okay, so square root 3 then it looks like and only the x is to the 1/4 power.

Answer 18

i believe its to the sqrt

Answer 19

144 and 729.

Answer 20

3 is sqrt, x and 1/4 are not in the sqrt

Answer 21

Yeah, thats how I solved it then, so those are the two answers.

Answer 22

thanks!

Answer 23

Want to help me with a few others since you have a calculator? (:

Answer 24

It would me a lot to me(:

Answer 25

mean*

Answer 26

Well, if they're ones I can go through an explaining process with then I'd like to do that, but if it's just ridiculous things like that then yeah, doesnt bug me, lol.

Answer 27

Geez, finally working again

Answer 28

i know.
\[x+\sqrt{x}-2\]

Answer 29

im running out of time . lol

Answer 30

solve for x again, right?

Answer 31

yeah ,quadratic form

Answer 32

Now this one we CAN do by normal factoring. Let sqrtx = u. Which then gives us:

\[u ^{2}+u -2 = 0\]

Answer 33

Easy one to factor here :P (u-1)(u+2)

Answer 34

(3x)^2-12(3x)+27

Answer 35

Oh, -9 and -3, that one is easy, too o.o

Answer 36

I mean (x-9)(x-3) where x = 3x xD

Answer 37

oh well i just put the -9,-3

Answer 38

Oh x_x

Answer 39

\[x-2\sqrt{x}-35\]

Answer 40

no solution,
49,
25,49,
25i,49
these are the choices