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OpenStudy (anonymous):
solve this de.
it says to show all step in your working out...i'm not sure what i have done is 'all steps'
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OpenStudy (anonymous):
\[x^3\frac{ dy }{ dx }+3x^2y=e^x\]
OpenStudy (anonymous):
so i know the answer but what would it mean by 'all steps'
OpenStudy (anonymous):
All i really did was find I(x)
then solved I(x)y=integral of I(x)Q(x)
OpenStudy (anonymous):
then solved for y
OpenStudy (anonymous):
would someone share me what they would do in reference to all steps..
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zepdrix (zepdrix):
What is I(x)? Is that your integrating factor that you found?
OpenStudy (anonymous):
yep!
zepdrix (zepdrix):
lol you had to do some work to find I(x).. not sure why you're confused about "show your work" lol XD
OpenStudy (anonymous):
alright this is what i did
OpenStudy (anonymous):
\[\frac{ dy }{ dx }+\frac{ 3 }{ x }y=\frac{ e^x }{ x^3 }\]\[I(x)=\exp(\int\limits_{?}^{?}\frac{ 3 }{ x })\]\[\exp(3\ln \left| x \right|)\]=\[x^3\]
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OpenStudy (anonymous):
\[yI(x)=\int\limits_{?}^{?}e^x \] as we are integrating x^3.e^x/x^3
OpenStudy (anonymous):
that is simply e^x +C
OpenStudy (anonymous):
THEREFORE
|dw:1375961438309:dw|
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