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A 6-kg bucket of water is being pulled straight up by a string at a constant speed. At a certain point the speed of the bucket begins to change. The bucket now has an upward constant acceleration of magnitude 3 m/s2. What is the tension in the rope now
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So I know the basic F=ma so 6x9.8=58.8 N, but what about the other part. of 3m/s2?
i think i understand. 9.8+3=12.8 12.8x6kg=76.8N can someone confirm
Sum of all forces = ma. If you draw a free body diagram you should see that: ma=T-mg. 6(3)=T-6(9.8)
we have to get the total acceleration to solve the problem. 9.8+3 ok, so i drew the diagram on my paper, worked it differently then what you suggested and go the exact same answer
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