Mathematics
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OpenStudy (anonymous):
Rewrite the expression in terms of the given function or functions. (sec x + csc x) (sin x + cos x) - 2 - cot x; tan x
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OpenStudy (anonymous):
tanx is the given function ?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
thats how its written
OpenStudy (anonymous):
lets first look at :
(secx + cscx)(sinx+cosx)
OpenStudy (anonymous):
and you should know that secx = 1/cosx and cscx = 1/sinx
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OpenStudy (anonymous):
so can you simplify it ?
OpenStudy (anonymous):
what is cscx its not on my calc?
OpenStudy (anonymous):
i just wrote it :) cscx = 1/sinx
OpenStudy (anonymous):
wow sry loll
OpenStudy (anonymous):
so can you do it now ?
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OpenStudy (anonymous):
1 sec
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
i get sec(x) for that prob up there
OpenStudy (anonymous):
and im wrong bc thats not a answer to choose from
OpenStudy (anonymous):
lets do it together since i got something else.
(secx + cscx)(sinx+cosx) = secxsinx + secxcosx + cscxsinx +cscxcosx = tanx + 1 + 1 + cotx
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OpenStudy (anonymous):
so (secx + cscx)(sinx+cosx) = 2 + cotx + tanx
now lets add it to the rest :
(secx + cscx)(sinx+cosx) - 2 - cotx = 2 + cotx + tanx -2 -2 - cotx = tanx
OpenStudy (anonymous):
ill be back in some minutes i hope it is enough though
OpenStudy (anonymous):
i must not be puttin it i mcalc right
OpenStudy (anonymous):
2tan x??
OpenStudy (anonymous):
@Coolsector
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OpenStudy (anonymous):
@britbrat4290 hey im sorry im back now
OpenStudy (anonymous):
as i wrote i got tanx
OpenStudy (anonymous):
shoot, ty
OpenStudy (anonymous):
yw .. say hey to the dolphin
OpenStudy (anonymous):
:)