Compute the standard deviation for the set of data. 2, 4, 6, 8, 10 @kelliegirl33
A. 2 sqr root of 2 B.8 c.2 sqr root of 10 D.64
its a fairly short list .... the mean is obviously 6; sum the squares of the differences and divide by 5; then sqrt it
A
would it be 30 divided by 5 wait, idk
i get a when i use a pencil ....
4,2,0,2,4 2(16+4) = 40/5 = 8 sqrt(8) = 2.2
30 is the sum of the set, /5 gives the mean of 6 the differences from the mean are: 4,2,0,2,4 square, add, divide and sqrt
Compute the standard deviation for the set of data. 13.3, 14.3, 15.3, 16.3, 17.3
the process is the same ...
15.3 is obviously the mean 1,2,0,2,1 1,4,0,4,1 = 10 10/5 = 2 and sqrt
I dont have a calc on me
well, 2,1,0,1,2 but thats immaterial
neither do i ....
lol
sqrt 2 is about 1.414 if memory serves
wow, awesome..... On a box-and-whiskers plot, what is the far left line called? a. minimum value c. median b. maximum value d. interquartile range
Last one for now, please help :_)
tell me which one youd pick first; this is pretty much conceptual and theres no way to really guide towards the answer
D
@amistre64 I would put D.
D isnot a good choice since the IQR range is in the middle ... |<-----|____|_______|-------------->| *** this denotes the leftmost line it either has to be the biggest or smallest value
Okay, well minimum value
minimum is what i would go with as well
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