A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27g of ANO3. What volume of the 0.150M solution can they make? I need someone to walk through the step with me, I sorta have an idea of what I'm doing, but I'm not sure if it's right

Question

anonymous · Answer

@GoldEverything

goldeverything · Answer

tell me what you know so i know if your doing it right or wrong

anonymous · Answer

Ok so first I know that I have a Molarity of 0.150
and a solution of 11.27g of ANO3

goldeverything · Answer

and what do you do after that

anonymous · Answer

I convert 11.27g to liters

goldeverything · Answer

do you know the next step

anonymous · Answer

and then to mL, and then to volume?

anonymous · Answer

I'm not sure, I know the steps for questions asked in a diiferent way, like How many grams of CaCl2 are needed to make 250 mL of 2.0 M CaCl2?, but I get confused when they change up what they are asking for

anonymous · Answer

so for this particular question, I'm not sure what the next step will be

goldeverything · Answer

there is no next step you solved it correctly

anonymous · Answer

huh?

goldeverything · Answer

you solved the equation correctly

anonymous · Answer

wait so how do I convert grams to Liters

anonymous · Answer

is it 11.27g ANO3*(100L/1g)=0.1127 L

goldeverything · Answer

correct

anonymous · Answer

r u sure that doesn't feel right?

goldeverything · Answer

its correct it doesn't feel right cause your not used to solving ti that way yet

anonymous · Answer

ok thanks

goldeverything · Answer

anytime