Question

can anybody please help me with this?

Answer 1

The first step to approach this question is to make everything on the same denominator, i.e. square root of 6.

\[\frac{ \sqrt{4} }{ \sqrt{3} } + \frac{ \sqrt{6} }{ \sqrt{2} } - \frac{ 4\sqrt{2} }{ \sqrt{6} }\] is the same as \[\frac{ \sqrt{2} \sqrt{4} }{ \sqrt{3} \sqrt{2}} + \frac{ \sqrt{3} \sqrt{6} }{ \sqrt{2} \sqrt{3}} - \frac{ 4\sqrt{2} }{ \sqrt{6} }\]

This is equal to

\[\frac{ \sqrt{8} + \sqrt{18} - 4\sqrt{2}}{ \sqrt{6} }\]

Simply the above to

\[\frac{ 2\sqrt{2} + 3\sqrt{2} - 4\sqrt{2} }{ \sqrt{6} }\]

you get

\[\frac{ \sqrt{2} }{ \sqrt{6}} = \frac{ 1 }{ \sqrt{3} } = \frac{ 1 }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{ \sqrt{3} }{ 3 }\]

If you don't understand anything, just lemme know...

Cheers :)

Answer 2

thanks a LOT!

Answer 3

My pleasure

Answer 4

Hi @m_sarvesh. Welcome to OpenStudy!

Great piece of explanation! Keep up the good work!