Suppose you have 54 feet of fencing to enclose a rectangular dog pen. The function a=27x-x^2, where x=width, gives you the area of the dog pen in square feet. What width gives you the maximum area? Round to the nearest tenth as necessary.
what is the axis of symmetry for your quadratic?
or if you know the calculus, define the derivative to be zero
This is for algebra, so to be honest, I'm not sure. My friend was looking at this problem, I was intrigued by it, so I tried it out.
do you know what the shape of the graph would look like?
there is also a factoring way to approach it; define the midpoint between the zeros
Well I do know that the answer is supposed to be width= 13.5 ft; area=182.3 ft squared
I'm real sorry, I didn't really know much background before asking this question, it's alright if you don't want to solve it
since this is algebra; lets define the values of x for which it is zero 27x-x^2 = 0 x (27-x) = 0 now, we should know that when we multiply anything by 0 we get 0; so this tells us that either: x = 0, 0 (27-0) = 0 or x = 27, 27 (27-27) = 0
a quadratic will have its minimum or maximum value (depending on how it opens) at the middle point between the zeros halfway between 0 and 27 is: 13.5
Hmmm.... so assuming that similar problems were taught in a school lesson, they would first have to instruct the class that the minimum/maximum is at the middle point between the zeros
in algebra class, they go over the properties of a quadratic equation; so this would have been reviewed at some point during the class yes
some quadratics never touch the x axis, so there are a few ways to approach this; this was just an easy one to assess by facoting
*factoring
So then what steps would I use to go about figuring out the maximum area? THANK YOU SO MUCH BY THE WAY
well, once you know the value for x, plug it in and work the 4th grade math skills ...
Alright, much appreciated, I really have to start easing back into math before school start ;)
good luck :)
Thanks!
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