Question

Write an equation in slope-intercept form

Answer 1

This is what I have so far
Using \[\frac{ y2-y1 }{ x2-x1 }\]
is \[\frac{ 4-(-2) }{-5-1 }\]
This gives me a slope (m) of -1

Answer 2

Using y-y1=m(x-x1)
That's point-slope form right?
I plug in what I have which gives me
y-4=-1(x-(-5)

Answer 3

Am I right so far?

Answer 4

\[y-y 1=\frac{ y 2-y1 }{ x2-x1 }\left( x-x1 \right)\]
Here (x1,y1) is (1,-2)
(x2,y2) is (-5,4)

Answer 5

So am I correct so far?

Answer 6

yes

Answer 7

OK so that gives me point slope of y-4=-1(x-(-5)
Correct?

Answer 8

y-(-2)=-1(x-1)

Answer 9

Then I distrubute the -1 which gives me
y-4=-1x+5
or
y-4=-1x-5

Answer 10

ok so would using 1,-2 be easier?

Answer 11

we have taken (x1,y1) as (1,-2)

Answer 12

OK That then using
y-(-2)=-1(x-1)
gives me y-(-2)=-1x+1

Answer 13

Right?

Answer 14

yes
we can also use y=mx+c
then we can take any point ,substitute it and get the value of c and finaly put the value of c

Answer 15

So to take it into slope-intercept for (y=mx+b)
I take -2=-1(1)+b

Answer 16

ok

Answer 17

Which gives me
-2=-1+b

Answer 18

now to solve for B...
?

Answer 19

b=-2+1=-1

Answer 20

hence y=-1x-1

Answer 21

OK! so that gives me
y=mx+b
will be
y=-1-1!

Answer 22

opps
y=-1x-1

Answer 23

yes

Answer 24

Thanks!

Answer 25

yw