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Mathematics 16 Online
OpenStudy (anonymous):

∫x^4-3/x

OpenStudy (psymon):

Well, the first term of your integral just follows the basic integration rule: \[\int\limits_{}^{}x ^{n}dx = \frac{ x ^{n+1} }{ n+1 }\]

OpenStudy (psymon):

As for the 2nd term, this follows the rule that: \[\int\limits_{}^{}\frac{ 1 }{ u }du = \ln u \] Of course can't forget + C, but yeah.

OpenStudy (psymon):

\[\int\limits_{}^{}(x ^{4} - \frac{ 3 }{ x })dx\] \[\int\limits_{}^{}x ^{4}dx - 3\int\limits_{}^{}\frac{ 1 }{ x }dx\] Think you could try it from there?

OpenStudy (anonymous):

Yes, thank you

OpenStudy (psymon):

Kk, awesome :3

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