Question

Solve the triangle. Round lengths to the nearest tenth and angle measures to the nearest degree. a = 7, b = 7, c = 5

A. A = 70°, B = 70°, C = 40°

B. A = 69°, B = 69°, C = 42°

C. A = 42°, B = 69°, C = 69°

D. A = 69°, B = 42°, C = 69°

Answer 1

hey

Answer 2

law of cosines for angle C:
c^2 = a^2 + b^2 - 2abcosC
25 = 49 + 49 - 2 * 49 * cosC
->
cosC = 0.7448979...
C = 41.85 -> C = 42 degrees
now for A and B :
A+B+C =180
A+B = 180 - 42
A+B = 138
since A = B we can find them :
2A = 138
A = B = 69


ANSWER IS B :)

Answer 3

thank u !!!