how do you find the limit of a function

Question

anonymous · Answer

attachment

anonymous · Answer

1) Lim (3x^4 + 2x^2-x+2)                                      x→ -2 
2) Lim (1 + 3x / 1 + 4x^2 + 3x^4)                           x→ 1 
3) Lim x^2 + x – 6 / x - 2 ;                                      x→ 2 
4) Lim x^2 – 9 / 2x^2 + 7x + 3                                x→ -3 
5) Lim x+2 / x^3 + 8                                                x→ -2

amistre64 · Answer

Lhop comes to mind; but the top zeros out before the bottom so id say its zero

anonymous · Answer

thanks lol 
Mr.Ami

anonymous · Answer

so whats the answer to the question

amistre64 · Answer

my view of it seems a little off tho, but we can still use it

anonymous · Answer

ok

amistre64 · Answer

lets try a different approach


x^2+2x
-------
   x^4



x^2         2x
---- +  -----
x^4         x^4



  1            2
---- +  -----
x^2        x^3

the limits of each part of the fucntion go off in 2 different directions towards the infinities

amistre64 · Answer

(+inf,+inf) + (-inf,+inf) ; no limit

anonymous · Answer

so the answer is no limit?

amistre64 · Answer

correct, my initial Lhop idea was flawed from start :/

anonymous · Answer

ok, thanks cutie

amistre64 · Answer

youre welcome