Question

!!Urgent Question!!

Two concentric conducting spherical shells produce a radially outward electric field of magnitude 49,000 N/C at a point 4.10 m from the center of the shells. The outer surface of the larger shell has a radius of 3.75 m. If the inner shell contains an excess charge of -5.30 μC, find the amount of charge on the outer surface of the larger shell. (k = 1/4ε0 = 8.99 × 109 N · m2/C2)

Answer 1

@souvik Do you have a minute to help? I'd appreciate it

Answer 2

i am not sure...but ..
if we consider a spherical guass surface of radius 3.75 m
we can calculate the amount of charges inside the sphere...
then we can find the charge on the outer surface of the larger shell..

Answer 3

Wouldn't it be zero? -5.3 on inner sphere and +5.3 on inner surface of outer sphere?

Answer 4

if it be zero then there shout be no electric field !!

Answer 5

I mean zero in the interior of the larger sphere. The outer should have a charge due to the electric field on the outside, right?

Answer 6

oh wait..! I read the question wrong..

Answer 7

i took a spherical guass surface of radius OA

Answer 8

Ok, I see, but what do I do now? I'm quite confused

Answer 9

now \[\int\limits_{}^{}E.ds=q/\epsilon\]
of E.4\(\pi\)r^2*\(\epsilon\)=q
if u have calculator...will u please calculate q ?

Answer 10

q=9.15*10^-5 C
q=91.5*10^-6 C
=91.5 uC
so the charge on the larger surface=91.5+5.30=96.8 uC