Question

HELP? :)

Logs...

Typing equation in a sec...

Answer 1

\[3\log_{3} (21)\]

Answer 2

Again. Use the property we used last time.
3log3(21)=x
You just have to find x.

Answer 3

So do I just kind of ignore the 3 in front of the log?

Answer 4

That's what confused me mainly..

Answer 5

Nah. First find the value of log3(21) and then multiply 3 with it.

Answer 6

Okay, I'm confused... could you explain more?

Answer 7

Eh wait. I think i'm doing this wrong. Just a min.

Answer 8

Okay, sorry ^^;

Answer 9

Ok you should know this property of logs.
a*log b(c) = [log b (c)]^a ..
yeah?

Answer 10

I didn't know, but now I do kind of XD

Answer 11

ah well. i am sorry but i'm confused again. sorry about that. :|
@kropot72 ?

Answer 12

is it \(\bf log_{3} (21) = x \ \ ?\)

Answer 13

No. There is no = sign anywhere.

Answer 14

or \(\bf 3log_{3} (21) \ \ \ ?\)

Answer 15

so just \(\bf log_{3} (21)\) ?

Answer 16

Yup, thats the one I posted.

Answer 17

well, I keep missing the 3 :/

Answer 18

Its the first one you did with the 3 in front of the log

Answer 19

\[3\log_3(21)=3\log_3(7 \times 3)=3\log_3(7)+3\log_3(3)=3\log_3(7)+3\]
\[3\log_3(7)=3\frac{\log_77}{\log_73}+3\]

Answer 20

\[3 (1-\log_73)+3=6-\log_73\]
answer can be in many forms..??

Answer 21

a.
21
c.
3
b.
-1
d.
1.04

Answer 22

It goes A, C, B, D.. IDK why XD

Answer 23

Using this..
\[3\log_3(21)=3\log_3(7 \times 3)=3\log_3(7)+3\log_3(3)=3\log_3(7)+3\]
\[3 \frac{\log_{10}7}{\log_{10}3}+3=3(0.4771)=1.4313\]
Using this..
\[6−\log_73=6-6-0.845=5.155\]
hmm dunno.

Answer 24

o_o

Answer 25

@terenzreignz to the rescue <3

Answer 26

\(\bigodot_\bigodot\)

Answer 27

...

Answer 28

hmmm, can you post a screenshot of the material?

Answer 29

no

Answer 30

The question looks exactly how I posted it here.

Answer 31

well, I can show you what I got \(\bf 3log_{3} (21) \implies log_3(21^3)\\
\textrm{using log change of base rule of } log_ab = \cfrac{log_cb}{log_ca}\\
log_3(21^3) \implies \cfrac{log_{10}21^3}{log_{10}3}\)

Answer 32

and it ain't any of your answers

Answer 33

....weird

Answer 34

though there's nothing wrong with it

Answer 35

Well I guessed XD Thanks for trying guys.