Question

The pH of a person’s blood is given by pH = 6.1 + log10 B - log10C, where B is the concentration of bicarbonate, which is a base, in the blood and C is the concentration of carbonic acid in the blood.

Use the Quotient Property of Logarithms to simplify the formula for blood pH.

Answer 1

\[pH=6.1 + \log (\frac{ 10b }{ 10c })=6.1 + \log (\frac{ b }{ c })\]

Answer 2

Well, if you just want answers ask him, he'll just flat out give them to ya x_x

Answer 3

But then what do I do... I dont know how to do these

Answer 4

That wasnt an answer.

Answer 5

None of my options looked like that so I think they did it wrong lol

Answer 6

It was, it only wants you to simplify it. There's no solving here.

Answer 7

...okay... but its not an answer... none of my choices look like that

Answer 8

When you have logs of the same base that are being subtracted, you can take the values and divide them under one log.
And sorry, he just annoys me for spitting out answers :/

Answer 9

I'm trying to tell you the thing he gave me is not an answer D: I'm looking at my choices right now

Answer 10

Yeah, I understood ya the first time. So what do your possible answers look like?

Answer 11

The closest thing I had to what he said was the same, except it was \[6.1+\log_{10} (b/c)\]

Answer 12

So here's the laws involved.\[\log_{10}(a) - \log_{a} (b) = \log_{a}\frac{ a }{ b }\]

the other is
\[c = \log_{a}(b) = b = a^{c}\]

Answer 13

When it is just written as log with no base, there is a sort of invisible base 10 there. So
\[\log_{10}x \] is the same as
\[logx \]
But for some reason my cimputer isnt showing the values properly, so I can't tell what is a base a power or anything right now.

Answer 14

just bring 6.1 to the other side like so .\[-6.1 = \log_{10} (\frac{b}{c})\]

Answer 15

Than use the second property I showed you above.

Answer 16

it has to be in ratio format: like
6.1:1
@mebs