I'm having trouble understanding how to solve this problem with limits. I'm going to post it in an attachment because I couldn't figure out how to type it on here.

Question

anonymous · Answer

attachment

jim_thompson5910 · Answer

the piecewise function breaks down into these 2 cases

f(x) = 1 if x is not equal to 2

OR

f(x) = 0 if x = 2

anonymous · Answer

So what would the graph look like? Is it two separate graphs or one graph with just two points?

anonymous · Answer

|dw:1375997860203:dw|

jim_thompson5910 · Answer

yes, the graph will essentially be the two graphs f(x) = 1 and f(x) = 0

the two whole graphs themselves won't be plotted since you have those restrictions

ex: you only plot y = 0 when x = 2

jim_thompson5910 · Answer

otherwise you plot y = 1 (when x is not 2)

jim_thompson5910 · Answer

and keep in mind there's a hole on y = 1 at x = 2

|dw:1375998373305:dw|

jim_thompson5910 · Answer

oh and (0,2) should be (2,0)

just catching that now

anonymous · Answer

@jim_thompson5910 , i know that but i thought since the hole is so small, i'd rather not put it there. haha. kinda got lazy