Question

What is the simplified form of 18 times g cubed times h to the ninth power all over 6 times g to the sixth power times h to the fifth power.

Answer 1

\[\large \frac{18g^3 h^9}{6g^6h^{15}}\] likek that?

Answer 2

yeah but its a 5 next to the h not a 15

Answer 3

\[\large \frac{18g^3 h^9}{6g^6h^{5}}\]

Answer 4

18 divide by 6 is 3 so you will have a 3 up top

Answer 5

\[\large \frac{18g^3 h^9}{6g^6h^{5}}\large =\frac{6h^{9-5}}{g^{6-3}}\] subtract the smaller from the larger if your job is to rewrite using only positive exponents

Answer 6

damn that was wrong, sorry numerator should have a 3 not a 6

Answer 7

\[\large \frac{18g^3 h^9}{6g^6h^{5}}\large =\frac{3h^{9-5}}{g^{6-3}}=\frac{3h^4}{g^3}\]

Answer 8

so basically you just divide everything? and subtract the exponent?

Answer 9

yes

Answer 10

not very hard, is it? really what you are doing is cancelling the common factors

Answer 11

thank you so much! this will help me with my other problems (: