What is the simplified form of the expression 4the square root of v. + 4 the square root of v to the sixth power. − the square root of the quantity 25 times v. − the square root of the quantity 9 times v to the sixth power.?
i dont know where to start..
\[4\sqrt{v}+4\sqrt{v^6}-\sqrt{25v}-\sqrt{9v^6}\]??
like that? hard to read
yes exactly that
ok fine lets take it step by step
\[\sqrt{v^6}\] is the square root of \(v^6\) since \(2\) goes in to 6 3 times, this is the same as \(v^3\)
another way to see it is \[\sqrt{v^6}=\sqrt{(v^3)^2}=v^3\]
now \(\sqrt{25v}=\sqrt{25}\times \sqrt{v}=5\sqrt{v}\)
and finally since we already know \(\sqrt{v^6}=v^3\) we know \[\sqrt{9v^6}=3v^3\]
now we have \[4\sqrt{v}+4v^3-5\sqrt{v}-3v^3\] and all that is left is to combine like terms
\(4v^3-3v^3=v^3\) and \(4\sqrt{v}-5\sqrt{v}=-\sqrt{v}\) for a "final answer" of \[v^3-\sqrt{v}\]
wow thats alot of steps, thank you so much, im going to go over and rad this a few times to fully unnderstand it, but hanks again so much!
it is a lot of steps but that is largely because i was explaining as i went along, and skipped nothing with some practice you can do most of this in your head
no steps were skipped, so if you really do read it, you will see all that you need to use to solve it
oh, and your welcome!
This man ( @satellite73 ) deserves a cookie :D lol
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