Question

what is the one of the real number values that must be exluded from the domain of the function

Answer 1

\[g(x)=\frac{ 3x-6 }{ x ^{2}-7x +12 } ?\]

Answer 2

hint:

solve for x

x^2 - 7x + 12 = 0

Answer 3

x=4?

Answer 4

that's one solution, what's another

Answer 5

but i only need one.... and i dont know others....
i substitute x from 1-8 :3 and got 4

Answer 6

smart thinking, plug in values to see which ones give you zero

another way is to factor and use the zero product property to solve

Answer 7

whats the zero product property?

Answer 8

if A*B = 0, then A = 0 or B = 0

Answer 9

so if you factored

x^2 - 7x + 12 = 0

to get

(x-3)(x-4) = 0

Answer 10

you can use the zero product property to go from

(x-3)(x-4) = 0

to

x-3 = 0 or x - 4 = 0

Answer 11

then you solve each equation

Answer 12

so x= 4 or x=3

Answer 13

yep, those two values make the denominator equal to 0, so they must be excluded

Answer 14

oh