Phosphorus has five valence electrons and hydrogen has one valence electron. What would be the Lewis dot (electron dot) structure for the covalent compound phosphorus trihydride?
As the name implies, phosphorous, "tri" meaning three hydride, meaning hydrogen. \(PH_3\) NOTE: I don't think that you may have learned stereochemistry, but there is in stereochemistry in phosphine.
http://hyperphysics.phy-astr.gsu.edu/hbase/pertab/perlewis.html http://hyperphysics.phy-astr.gsu.edu/hbase/chemical/lewis.html#c1 http://hyperphysics.phy-astr.gsu.edu/hbase/chemical/lewis.html#c2 Very good resource site. I'm not the best at physics, but I knew that the answer was not \(\sf PH_3\).
Since \(\sf P\) has \(5\) electrons in it's outermost shell, and it will tend to get \(8\), it will share \(3\) with other atoms. Or take them, or something.. I haven't calculated what type of bond would take place in a while. If the bonds are covalent, they are shared, I think. So, \(\sf P\) would have two dots on all four sides of it, and \(\sf H\) atoms on three sides.
I did a quick Google search and it looks like I'm right. So do you see what you need to do?
PH3 is trigonal pyramidal (just like ammonia NH3), 3 bonds (6 e) 1 lone pair (2e). |dw:1376052275099:dw|
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