f=9/5 C + 32 solve for fahrenheit
It's done.
have you tried?
lol @mathstudent55
Bianca, the equation is already solved in terms of Fahrenheit. Do you have a specific Celcius that you need to plug in?
Isn't it already solved for \(Fº\)?
yes it is a manipulating literal equation
Can Anyone please explain me how to derive the formula :- f=9/5 C + 32
You need to ask your questions in another thread @goformit100 not post a questions within someone else's question. http://openstudy.com/code-of-conduct
@goformit100 There is no "derivation" of this formula it is just used for conversion between scales.
@Preetha is there derivation" of this formula ??
in mean this is the problem theres a degree in f so 'f=9/5'c+32
Ok HELP HERE... http://openstudy.com/study#/updates/520475cbe4b01dab337024fd for the derivation
@ailabianca it looks like you need to learn more about Solving Literal Equations. http://www.purplemath.com/modules/solvelit.htm Basically, it is an application of the order of operations, but in reverse. You are looking to move things around until you isolate the goal. \(x=\dfrac{y}{2}+5\) solve for y. Normally, division happens first and addition last, but you are undoing things, so you cancel the addition first with a subtraction: \(x-5=\dfrac{y}{2}+5-5 \implies x-5=\dfrac{y}{2}\) Now you need to multiply through by 2. \((x-5)\cdot 2=\dfrac{y}{2}\cdot 2\implies 2x-10=y\) Your question would work the same way, but it is already solved for F.
Every term is in degrees: \(F^{\circ}=9/5 C^{\circ} + 32^{\circ}\)
thank you
np. They just leave off the degrees most times because it is understood.
Remember to close things when you are done. \(\large\ddot \smile\)
x=A(B+C) solve for c
OK.... so, remember what I said about you have to undo things in reverse order from normal order of operations? So what do you need to get rid of first from near C?
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