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Mathematics 9 Online
OpenStudy (anonymous):

the second term in a geometric sequence is 12 the forth term in the same sequence is 4/3. what is the common ratio in this sequence

terenzreignz (terenzreignz):

In a geometric sequence, each term is the previous term multiplied by a constant known as the common ratio. Now, if the common ratio is r, and the second term is 12, what is the third term?

OpenStudy (anonymous):

the third term is 12r?

terenzreignz (terenzreignz):

That's right, and the fourth term is...?

terenzreignz (terenzreignz):

I know it's 4/3, but what is it in terms of the second term (12) and r?

OpenStudy (anonymous):

12r^2?

terenzreignz (terenzreignz):

That's correct ^_^ So the fourth term is \(12r^2\) but you also know it to be \(\Large \frac43\) Then \[\Large 12r^2 = \frac43\] You may now simply solve for r.

OpenStudy (anonymous):

thank you!

terenzreignz (terenzreignz):

No problem... though you can thank me by posting your answer :P

OpenStudy (anonymous):

.33?

terenzreignz (terenzreignz):

I prefer \(\Large \frac13\) But you're correct ^_^

OpenStudy (anonymous):

care to help me with another one? :)

terenzreignz (terenzreignz):

Let's see it...

OpenStudy (anonymous):

the original value of a car is 18000$ and it depreciates by 15% each year. What is the value of the car after three years?

terenzreignz (terenzreignz):

Ahh... word problems... trust me, solving these things is usually easy (almost child's play) but then again, the tricky part is setting up EXACTLY WHAT TO SOLVE... What are your ideas? ^_^

OpenStudy (anonymous):

well im looking for the 3rd term in a sequence?

terenzreignz (terenzreignz):

Yeah, I know, but how do you plan to solve this?

OpenStudy (anonymous):

by using the first equation you gave me?

terenzreignz (terenzreignz):

In this context, you can probably expect a geometric sequence to be involved...

terenzreignz (terenzreignz):

Okay, a good place to start would be to seek a common ratio... if you slash 15% off something, what remains?

OpenStudy (anonymous):

youd have 15300

terenzreignz (terenzreignz):

LOL, I meant in general, if you slash 15% off of something, you get 85% remaining right?

OpenStudy (anonymous):

oh yeah lmao but would the answer be 11054.25?

terenzreignz (terenzreignz):

I actually don't know. But what I meant is that when you slash off 15% of something, it's the same as multiplying it by 85% or 0.85 right?

OpenStudy (anonymous):

yeah it is

terenzreignz (terenzreignz):

So every year, you multiply it by 0.85, and three years have passed... so how many times do you multiply the original price by 0.85?

OpenStudy (anonymous):

three times

terenzreignz (terenzreignz):

You see where the concept of a geometric sequence plays in, you can consider 0.85 as the common ratio...

terenzreignz (terenzreignz):

So, the answer, is after three years, the new value is \[\Large 18000\times 0.85^3\]

OpenStudy (anonymous):

and that gives you the answer that i previously stated, Thank you very much!! i wanted to check if i was correct :)

terenzreignz (terenzreignz):

I had to make sure YOU knew how to do it in general... say, if we change the discount, of if it were 10 years or something :P

OpenStudy (anonymous):

\[18000*.85^{10}\]

terenzreignz (terenzreignz):

LOL yeah :) What if it were 10 years, but a 12% discount instead of 15% ?

OpenStudy (anonymous):

\[18000*.88^{10}\]

terenzreignz (terenzreignz):

You seem to have mastered it already XD

terenzreignz (terenzreignz):

Good job ^_^

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