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Mathematics 20 Online
OpenStudy (math2400):

urgent help if anyone could quickly explain this? pic:

OpenStudy (math2400):

OpenStudy (usukidoll):

we have a piece by piece graph.

hero (hero):

All you have to do is input the values and understand the behavior near a particular x value of interest.

OpenStudy (usukidoll):

the domain restrictions are in the denominator.

OpenStudy (usukidoll):

if you don't have a problem with a denominator, it's most likely going to be continuous. However you need to follow the rules that it tells you on the right hand side.

OpenStudy (zzr0ck3r):

no its not...end points are the problem most of the time

hero (hero):

If you observe the behavior of the first two functions as either side approaches x = 0 for example, then you will notice something of interest about them.

OpenStudy (usukidoll):

and how the heck am I going to graph 1/x if x = 0? that's not happening dude.

OpenStudy (zzr0ck3r):

you can sort of cheat lets look at 1+x^2 and 2-x notice that the first is for x<=0 and the second is for x>0 but to check we plug in 0 to both 1+0^2 does not equal 2-0 so we have discontinuity at x = 0

OpenStudy (math2400):

i feel like im getting mixed answers..let me take a take a look. sorry its really late here and im exhausted lol

OpenStudy (usukidoll):

oh! Discontinuity ok.. it occurs when you have a jump and a donut hole

OpenStudy (math2400):

correct @UsukiDoll

OpenStudy (usukidoll):

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