Question

Plz can anybody suggest me a book which will make math base good?. My base in math is very poor.

Answer 1

Get the Handbook of Mathematics for Engineers

Answer 2

Well, I guess it depends on what level you're on, but it's a great math reference book

Answer 3

in 11

Answer 4

These are all good questions...but if you're interested in ONE book, then the book I suggested is the one. If you have any doubts, go to a book store and peruse the book before buying it

Answer 5

Thanks Hero can u suggest any book which will improve trignometry?

Answer 6

I have a trig book. I'll just give it to you Whether it is good or not is relative to the individual. What one person might say is great, another person might not agree. But truthfully, whether or not any particular book resonates with you depends on your level.

Answer 7

u r rit Hero

Answer 8

r u sending the book?

Answer 9

What you probably need is a good book PLUS someone to answer your questions as they arise. It will take me some time to create a link to the book. Once I have done so, I'll message it to you.

Answer 10

Thanks Hero :)

Answer 11

interactmath.com is a free resource with tons of practice problems from lots of textbooks. They even have the option to walk thru the solution process.

Answer 12

7 months have passed... how do u feel now ha :)

Answer 13

need more practise

Answer 14

Lol

Answer 15

my oly recommendation is, if you're spending time on learning stuff, spend it wisely,
spend it on learning stuff correctly..

below are excellent resourses for a 12th grader :

singel variable calculus :
http://ocw.mit.edu/courses/mathematics/18-01-single-variable-calculus-fall-2006/video-lectures/

multivariable calculus :
http://ocw.mit.edu/courses/mathematics/18-02-multivariable-calculus-fall-2007/video-lectures/

differential equations :
http://ocw.mit.edu/courses/mathematics/18-03-differential-equations-spring-2010/video-lectures/

Answer 16

it wud take atleast another year to do those courses and digest them... good luck ! :)

Answer 17

I thoroughly recommend going to khan academy, they cover 1st grade to advanced in a relatively easy to understand form

Answer 18

over a book that is

Answer 19

i like khanacademy for kindergarten to 12th grade levels
i dont recommend it for higher levels

Answer 20

it's good for calc

Answer 21

just personal opinion lol

Answer 22

MIT is a better place for calc

Answer 23

lol I liked it up to calcs and some linear algebra

Answer 24

but it's also a lot harder to understand

Answer 25

khan is like the easy to understand version of mit lol

Answer 26

lol

Answer 27

but base i interpreted as basic, so that's why khan>mit ;)

Answer 28

i dont think so, MIT is the best in industry lol, khan is for range-of-the-moment pleasure folks... MIT is for long-term math pursuing ppl ;)

Answer 29

ie basic vs detailed

Answer 30

lol

Answer 31

I thought this was for basic math?

Answer 32

khan is good for basic math < 12 ... non debatable :)

Answer 33

i guess my question would be, what does @Alivewidmusic need practice with at this time? any specifics?

Answer 34

trig annoys me most of the time

Answer 35

yea and mit is good for advanced topics non debatable :P

Answer 36

do you have an example problem that you've had trouble with?
or maybe what topic is being covered that is causing you troubles.

Answer 37

ok then yea, @Alivewidmusic you should be able to understand khanacademy.com They have some things in other languages too, but you can take their preliminary test, and they will place you so that you can practice.

Answer 38

whoops it's khanacademy.org

Answer 39

dont remember the prob.. bust its jus substituting problem answers get wrong

Answer 40

hm...
something like this: \( \cos \left( \sin^{-1} \dfrac{a}{b} \right) \)?
or using trig identities well?
i don't think we're referring to the trig substitution for calc, which was my first idea of trig sub.

Answer 41

yes similar to that

Answer 42

for problems much like that, my best tip is learning how to fill out the right triangles. really!

a lot of those problems start by looking at the interior: \( \theta = \sin^{-1} \dfrac{a}{b} \) or \(\sin \theta = \dfrac{a}{b} \) by taking inverse of both sides.
that last bit tells us the \(\text{opposite}\) length to \(\theta\) divided by the \(\text{hypotenuse}\) length. \( \sin \theta = \dfrac{a}{b} = \dfrac{\text{opposite}}{\text{hypotenuse}} \)
so we can fill out two of three sides on a right triangle. the last one becomes available throguh pythagorean thm

and then we just have to find \(\cos \theta \) with the newly identified adjacent length.

the same idea often permeates these sorts of problems. being able to draw and fill out all side lengths / possibly angles on the triangle should be powerful.

Answer 43

hmm have to practise

Answer 44

i've been looking around a bit. it's hard to find this particular one (i didn't know what it would be called, so it took 4 searches). this looks like a good source of both guidance and practice problems:
http://www.ck12.org/book/CK-12-Trigonometry-Concepts/r2/section/4.6/