if cosx = 2/3 and x is in quadrant 4, then sin x/2=?
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OpenStudy (anonymous):
answer choices:
A) 1/3
B) Rad (1/6)
C) -1/3
D)-Rad(1/6)
OpenStudy (anonymous):
first you need \(\sin(x)\)
OpenStudy (anonymous):
do you know how to find it?
in other words: if you know \(\cos(x)=\frac{2}{3}\) can you find \(\sin(x)\) ?
OpenStudy (anonymous):
/\[\sqrt{\sqrt{5}}/3\] right?
OpenStudy (anonymous):
forget the 2nd rad on the 5
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OpenStudy (anonymous):
yes, but now i just realized i steered you wrong, since
\[\sin(\frac{x}{2})=\pm\sqrt{\frac{1-\cos(x)}{2}}\] so really you do not need \(\sin(x)\) for this, i was mistaken (you were right though)
now we have some arithmetic to do , and also have to figure out if it is plus or minus
since \(x\) is in quadrant 4, \(\frac{x}{2}\) is in quadrant 2, therefore \(\sin(\frac{x}{2})\) is positive
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