Question

can anybody please help me with this?

Answer 1

R u familiar with conjugate?

Answer 2

yes...

Answer 3

can u pls tel me the conjugate of \(2-\sqrt3\)

Answer 4

\[2 + \sqrt {3}\]

Answer 5

yup good:)
Nw when u multiply the numerator nd the denominator of the given fraction by it what do u get?

Answer 6

\[\frac{ 4 \times 2 + \sqrt {3} }{ 4 - \sqrt ({3})^{2} }\]

Answer 7

right?

Answer 8

you should put things in parens

Answer 9

\[\frac{4(2+\sqrt3)}{4-(\sqrt3)^2}\]
\[(\sqrt3)^2=?\]

Answer 10

3 ?

Answer 11

yup right:)
nw can u simplify ur fraction?

Answer 12

what do you get for the bottom ?

Answer 13

\[\frac{ 8 + \sqrt {3} }{ 1 }\]

Answer 14

like this?

Answer 15

pls check ur numerator again:)

Answer 16

the bottom is ok

the top, you distribute: the 4 times *each* term

Answer 17

think of the parens as a package, and you have 2 packages
that means you have 2 of everything inside the package

Answer 18

in your case, you have 4 of everything inside the parens

Answer 19

is D the correct answer?

Answer 20

@phi

Answer 21

the top is 4(2+sqrt(3) )
after distributing the 4 you get
4*2 + 4* sqrt(3)
which can be written
8 + 4sqrt(3)

Answer 22

thanks a lot :)