need help inserted pic
Are you trying to divide the equations?
idk what to do
simplify
Start by factoring the numerator and denominator.
@alffer1
im confused sorry guys idk what im doing
There is no solve here. This is not an equation since there is no equal sign. This is simply the division of two polynomials. First, factor the two trinomials.
idk what you are saying
Do you not know how to factor? \[(a^2 + abx + b^2)\]\[(a \pm b) (a \pm b)\]
k ill figure it out myself
Thats not what I meant. Listen to what @mathstudent55 is saying/typing...
still i aint good at math so
Lets start with the first one then.. What two numbers when multiplied together equal 14 also give you 9 when added? Like 4 and 3 give you 7 when added and 12 when multiplied...
You need to factor the numerator and the denominator. \(\dfrac{x^2 + 9x + 14}{x^2 + 11x + 28} \) Both the numerator and denominator are trinomials of the form \(x^2 + ax + b \). The factoring for both is a simple, one-step process.
For the numerator, you need to find two factors of 14 that add to 9. What are two numbers that multiply to 14 and add to 9?
7 and 2
Great. Now let's look at the denominator. It's a similar procedure. What are 2 numbers that multiply to 28 and add to 11?
7 and 4
Great. Now we can factor both the numerator and the denominator: \(\dfrac{(x + 7)(x + 2)}{(x + 7 )(x + 4) } \)
Now you see that we have a common factor in the numerator and the denominator. We can reduce the fraction by dividing the x + 7 factor in the numerator by the x + 7 factor in the denominator.
is it x+2 over x+7
\(\dfrac{\cancel{(x + 7)}(x + 2)}{\cancel{(x + 7 )}(x + 4) }\) \(\dfrac{x + 2}{x + 4 }\) This is the final answer.
Be careful, the two factors of x + 7 were canceled. We are left with x + 4 in the denominator.
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