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Physics 14 Online
OpenStudy (anonymous):

2 Questions based on KINEMATICS......HELP REQUIRED!!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

@agent0smith @Ashleyisakitty @april115 @andriod09 @BulletWithButterflyWings @e.cociuba @terenzreignz @timo86m @yrelhan4 @Phoenixuncaged @Luigi0210 @Loser66 GUYS/GALS PPPPPLLLLLLLLLLSSSSSSSSSSS HELP!!

OpenStudy (anonymous):

@NaCl @nincompoop

OpenStudy (anonymous):

:c I dont know how to do dis -.-

OpenStudy (anonymous):

No prob..Cheers!!....But I really need the friggin ans/method!!

OpenStudy (agent0smith):

Attaching it sideways really doesn't help :P

OpenStudy (anonymous):

are you there?

OpenStudy (anonymous):

exir.ru/solutions/Kinematics.htm this could help .. Found few similar sums

OpenStudy (anonymous):

@agent0smith @Ashleyisakitty @april115 @andriod09 @BulletWithButterflyWings @e.cociuba @terenzreignz @timo86m @yrelhan4 @Phoenixuncaged @Luigi0210 @Loser66

OpenStudy (anonymous):

AC looks like diameter right ?

OpenStudy (anonymous):

Ya

OpenStudy (anonymous):

well g along AC (call it gc) equals g g along AD (call it gd) equals gcosa and gb equals gcos(a/2) agree so far ?

OpenStudy (anonymous):

Figured that!!

OpenStudy (anonymous):

now, if AC is the diameter so AB = AC*cos(a/2) AD = AC*cos(a)

OpenStudy (anonymous):

agree ?

OpenStudy (anonymous):

Yup

OpenStudy (anonymous):

so now use y = gt^2/2

OpenStudy (anonymous):

Wat answer do u get.Pls post ur work!!:)

OpenStudy (anonymous):

for AB we get: AC*cos(a/2) = gcos(a/2)*(tb)^2/2 AC = g(tb)^2/2

OpenStudy (anonymous):

looks like the times are equal

OpenStudy (anonymous):

so c,b,d are the answers

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

On to the next one,I guess!!

OpenStudy (anonymous):

mmm

OpenStudy (anonymous):

i did something, i would like to hear though what would you do

OpenStudy (anonymous):

i mean, i got one of the answers there

OpenStudy (anonymous):

take v=5t for 1st case!! I will take u=v=5t.......for second case!!

OpenStudy (anonymous):

|dw:1376136491172:dw|

OpenStudy (anonymous):

Is my meth correct??

OpenStudy (anonymous):

vav = (v1 + v2)/2 vav = (0.25v,vsqrt(3)/4) |vav| = v/2

OpenStudy (anonymous):

that is what i did anyway

OpenStudy (anonymous):

How did u get v1=0.25v??

OpenStudy (anonymous):

no, v1 = (v,0)

OpenStudy (anonymous):

So wats 0.25v....Pls sho the calculations!1

OpenStudy (anonymous):

v1 , v2 are vectors .. look at what i draw

OpenStudy (anonymous):

v1 + v2 = (v,0) + (-vcos60,vsin60) = (0.5v,vsqrt(3)/2) so vav = (v1+v2)/2 = (0.25v,vsqrt(3)/4) <- this is a vector!! now take its magnitude and get v/2

OpenStudy (anonymous):

The drawing's not helpin...:( CAn u do a wrtiten post??

OpenStudy (anonymous):

*written

OpenStudy (anonymous):

Hand drawn I mean!!

OpenStudy (anonymous):

Or draw it a bit btr with the sides!!

OpenStudy (anonymous):

|dw:1376136880838:dw|

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