Question

1 - 6i is a zero of f(x) = x^4 - 2x^3 + 38x^2 - 2x + 37.
How would I find another zero?

Answer 1

Imaginary zeros always come in pairs, I believe, in the form \[a \pm bi\]
So you can get another zero by just slightly modifying the one you know!

Answer 2

it is the conjugate
what @BangkokGarrett said

Answer 3

I was thinking that but it seemed to easy and I have to explain the process in how I found it, I'm not sure if they would accept me using 1+6i

Answer 4

or am I just overthinking it