Question

Using Logarithms how would I go about solving the following?

1+ 2^x = 8

I currently have:

log1 + 2logx = log8

Answer 1

I can get 2logx = log8 - log1 but it doesn't make sense to me, please help. Thanks.

Answer 2

2^x = 7
then, taking logs of both sides
x * log 2 = log 7

Answer 3

dunno about the logs dude, but logic would indicate that 1 + 7 = 8
so 2^x = 7
so x = log 7/ log 2

Answer 4

ah, my bad, wolf has faster internets ;D

Answer 5

you guys are both right! its just x = log7/log2. Thanks guys!

I wish I can give out two medals :(

Answer 6

Thanks zeno

Answer 7

Thank you Wolf, I'll find something more challenging next time ;-)

Answer 8

That was challenging enough