Using Logarithms how would I go about solving the following?

1+ 2^x = 8

I currently have:

log1 + 2logx = log8

Question

Using Logarithms how would I go about solving the following?

1+ 2^x = 8

I currently have:

log1 + 2logx = log8

anonymous · Answer

I can get 2logx = log8 - log1 but it doesn't make sense to me, please help. Thanks.

wolf1728 · Answer

2^x = 7
then, taking logs of both sides
x * log 2 = log 7

jack1 · Answer

dunno about the logs dude, but logic would indicate that 1 + 7 = 8
so 2^x = 7
so x = log 7/ log 2

jack1 · Answer

ah, my bad, wolf has faster internets    ;D

anonymous · Answer

you guys are both right! its just x = log7/log2. Thanks guys!

I wish I can give out two medals :(

wolf1728 · Answer

Thanks zeno

anonymous · Answer

Thank you Wolf, I'll find something more challenging next time ;-)

wolf1728 · Answer

That was challenging enough