Question

Solve for x:x^2-sq. root(15)x-2i=0

Answer 1

\[x^2-\sqrt{15x}-2i=0?\]

Answer 2

x is outside the root

Answer 3

\[x^2-\sqrt{15}x-2i=0?\]

Answer 4

yup

Answer 5

\[x^2-\sqrt{15}x-2i=0\\(x-\frac{\sqrt{15}}{2})^2= 2i+(\frac{\sqrt{15}}{2})^2\\x=\pm\sqrt{2i+\frac{14}{4}}+\frac{\sqrt{15}}{2}\]

Answer 6

do you now how to complete the square?

Answer 7

yes

Answer 8

that should say 15/4 not 14/4

Answer 9

k

Answer 10

ok, well that's all I did

Answer 11

\[ax^2+bx+c=0\\a(x+\frac{b}{2})^2=-c+a(\frac{b}{2})^2\]

Answer 12

got it

Answer 13

good deal