f[g(2)]= f[h(3)]=
f(x)=2x, g(x)=3x-2, h(x)=x^2-4
First calculate g(2) this is done by substituting 2 for x in g(x) g(2)= 3(2)-2=6-2=4. Now you substitute that value in the f(x).
f[g(2)=f(x)=2(4)=8 Here we are now substituting for x in f(x) our new found value of g(2). For the first one the solution is 8. The next one is very similar except you are going to use h(2) in f(x)=x^2-4.
f(2)=2^2-4
h2=0
h=0
As before we first find h(x) for h(3) by replacing the x in h(x) with 3, or h(3)=3^2-4 h(3)=9-4=5 did you follow that.
Oh ya
Now our new found value of 5 is substituted in the f(x)=2x giving us f(5)=2x=2(5)=10 substituted our new found value 5 for the x in f(x)=2x
That is how the second one can be done. Please review the above and ask questions if you have any. Don't just say I'm confused lol.
oh,Sorry.
2(5)=10
Did you follow with understanding?
Not sure.
I'm pretty stupid.
Yes 10 was the solution of the second one
Oh yay!
If you were stupid you couldn't play the trumpet.
lol, no that's just my talent.
I think you are getting a handle on these things. I must admit when you first start doing them they seem very convoluted, but eventually you will see why you are learning these problems with functions.
Have you ever heard the expression, "ours is not to wonder why, but just to do or die."
no
I think that has more of a military context, but is a little bit appropriate. Good luck with them.
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