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Mathematics 7 Online
OpenStudy (anonymous):

f[g(2)]= f[h(3)]=

OpenStudy (anonymous):

f(x)=2x, g(x)=3x-2, h(x)=x^2-4

OpenStudy (radar):

First calculate g(2) this is done by substituting 2 for x in g(x) g(2)= 3(2)-2=6-2=4. Now you substitute that value in the f(x).

OpenStudy (radar):

f[g(2)=f(x)=2(4)=8 Here we are now substituting for x in f(x) our new found value of g(2). For the first one the solution is 8. The next one is very similar except you are going to use h(2) in f(x)=x^2-4.

OpenStudy (anonymous):

f(2)=2^2-4

OpenStudy (anonymous):

h2=0

OpenStudy (anonymous):

h=0

OpenStudy (radar):

As before we first find h(x) for h(3) by replacing the x in h(x) with 3, or h(3)=3^2-4 h(3)=9-4=5 did you follow that.

OpenStudy (anonymous):

Oh ya

OpenStudy (radar):

Now our new found value of 5 is substituted in the f(x)=2x giving us f(5)=2x=2(5)=10 substituted our new found value 5 for the x in f(x)=2x

OpenStudy (radar):

That is how the second one can be done. Please review the above and ask questions if you have any. Don't just say I'm confused lol.

OpenStudy (anonymous):

oh,Sorry.

OpenStudy (anonymous):

2(5)=10

OpenStudy (radar):

Did you follow with understanding?

OpenStudy (anonymous):

Not sure.

OpenStudy (anonymous):

I'm pretty stupid.

OpenStudy (radar):

Yes 10 was the solution of the second one

OpenStudy (anonymous):

Oh yay!

OpenStudy (radar):

If you were stupid you couldn't play the trumpet.

OpenStudy (anonymous):

lol, no that's just my talent.

OpenStudy (radar):

I think you are getting a handle on these things. I must admit when you first start doing them they seem very convoluted, but eventually you will see why you are learning these problems with functions.

OpenStudy (radar):

Have you ever heard the expression, "ours is not to wonder why, but just to do or die."

OpenStudy (anonymous):

no

OpenStudy (radar):

I think that has more of a military context, but is a little bit appropriate. Good luck with them.

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