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Mathematics 13 Online
OpenStudy (anonymous):

can anybody please help me with this?

terenzreignz (terenzreignz):

What have we here? :)

OpenStudy (anonymous):

\[\frac{ (3-2i) (5-i) }{ 5^{2} - i ^{2} }\] is this correct? for the next step?

terenzreignz (terenzreignz):

Whoops, I meant \[\Large \frac{3-2i}{5+i}\]sorry

terenzreignz (terenzreignz):

You started with that ^ ?

OpenStudy (anonymous):

yes

terenzreignz (terenzreignz):

You learn quickly... Good job :)

OpenStudy (anonymous):

:) I have a good teacher

terenzreignz (terenzreignz):

Now, the bottom part is just 5 - ( -1 ) which is just 6, so worry about that later... Simplify the numerator? :)

terenzreignz (terenzreignz):

Just FOIL away lol. You can treat the i like any variable, and just simplify later...

terenzreignz (terenzreignz):

Are you still there, @RH ?

OpenStudy (anonymous):

Yes sorry @terenzreignz my laptop froze :(

terenzreignz (terenzreignz):

Thaw it out :P Now, about simplifying the numerator...?

OpenStudy (anonymous):

is the numerator like this \[15 - 3i - 10i -2i\]

terenzreignz (terenzreignz):

We seem to have a problem with \[\Large -2i \times -i \] try multiplying them again... but it's definitely not -2i :)

OpenStudy (anonymous):

-2iˆ2

terenzreignz (terenzreignz):

we... have a problem... remember that negative times negative is positive... \[\Large -2i \times -i = +2i^2\]

OpenStudy (anonymous):

yes sorry!!! :(

terenzreignz (terenzreignz):

LOL okay, so what is \(\large 2 i^2 = \color{red}?\)

OpenStudy (anonymous):

15-13i + 2iˆ2/ 25 - (-1). is this correct?

terenzreignz (terenzreignz):

LOL yeah, but, what is \(\large 2i^2 = \color{red}?\) Never ever forget that \(\large i^2 = -1\) :D

OpenStudy (anonymous):

2iˆ2= -2 ?

terenzreignz (terenzreignz):

That's right.

terenzreignz (terenzreignz):

So it can be simplified further :)

OpenStudy (anonymous):

so \[\frac{ 13 - 13i }{ 26 }\] is the answer?

terenzreignz (terenzreignz):

Well, almost :P You CAN simplify that...

terenzreignz (terenzreignz):

Factor out the 13...

terenzreignz (terenzreignz):

\[\Large \frac{13(1-i)}{26}\]

OpenStudy (anonymous):

@terenzreignz thanks! but that is not in the choices :(

terenzreignz (terenzreignz):

Of course not... what is 13/26?

OpenStudy (anonymous):

hmm I am not sure how to simplify that :S

terenzreignz (terenzreignz):

Seriously? LOL \[\Large \frac{13}{26}\] This is elementary 'simplifying fractions to lowest terms' D: Never \(\color{red}{ever}\) forget the basics!!!! Come on, look at it again, I believe in you :)

OpenStudy (anonymous):

Ooo sorry I didnt understand the question!!!

terenzreignz (terenzreignz):

Okay, so, what is 13/26?

OpenStudy (anonymous):

26 can be simplified if it is divided by 13 and it equals 2 ?

terenzreignz (terenzreignz):

Yes... so, canceling out, you get...?

OpenStudy (anonymous):

13/2

terenzreignz (terenzreignz):

I would like to emphasize that you really shouldn't be having trouble with arithmetic D: \[\Large \frac{13(1-i)}{26}=\frac{\cancel{13}^1(1-i)}{\cancel{26}^2}\]

terenzreignz (terenzreignz):

Is that in the choices now? :)

OpenStudy (anonymous):

YES! thank you so much!

terenzreignz (terenzreignz):

Extra emphasis on basics... Your teachers are teaching you algebra on the assumption that you have pretty much mastered arithmetic, so do yourself a favour and master it :D

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