Find the sum of the first 8 terms of the sequence. Show all work for full credit. 1, -3, -7, -11, ...
Do you notice the pattern?
Could you say what the next term is?
here a=1, d= -3-1=-4, n=8 since\[s_n=\frac{n}{2}[2a+(n-1)d] \rightarrow s_8=\frac{8}{2}[2\times 1+(8-1)(-4)]\] \[=4[2+7(-4)] =4[2-28] =4[-26] =-104\]
Seriously, bro?
Yes..
Giving a student the answer almost never results in learning. So if you state the answer instead of leading them to find it on their own, your "teaching" is worthless.
And in this case it nullifies others' efforts at actually teaching.
This is called an arithmetic series. The solution is easy to find when you see the pattern as @SmoothMath indicates. This will be very helpful: http://en.wikipedia.org/wiki/Arithmetic_series
haha thanks guys, I appreciate the help @SmoothMath @dpasingh
read this....it explains well http://www.regentsprep.org/Regents/math/algtrig/ATP2/ArithSeq.htm
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