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PRECALC QUESTION! Convert the polar representation of this complex number into its standard form: z = 2(cos 11pi/6+ i sin 11pi/6)? A. sqrt(3) -i B. 1- sqrt(3) i C. -sqrt(3)/ 2 -(1/2) i D. -sqrt(3) + i
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Find the cos and sin of 11pi/6 and substitute that inside of the parenthesis, then just distribute the 2 inside.
I dont know how.. I'm getting a weird answer
DO you know the values of cos and sin at 11pi/6?
yes cos 11pi/6 is sqrt(3) /2 and sin is (-1/2)
Correct. So then we would substitute that and have. \[2(\frac{ \sqrt{3} }{ 2}-i \frac{ 1 }{ 2 })\] Now just multiply the 2 in :3
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Ohh okay got it, thank you!! :D
Yep, not that bad :P
Good luck ^_^
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