Question

PRECALC QUESTION!
Convert the polar representation of this complex number into its standard form:
z = 2(cos 11pi/6+ i sin 11pi/6)?

A. sqrt(3) -i
B. 1- sqrt(3) i
C. -sqrt(3)/ 2 -(1/2) i
D. -sqrt(3) + i

Answer 1

Find the cos and sin of 11pi/6 and substitute that inside of the parenthesis, then just distribute the 2 inside.

Answer 2

I dont know how.. I'm getting a weird answer

Answer 3

DO you know the values of cos and sin at 11pi/6?

Answer 4

yes cos 11pi/6 is sqrt(3) /2 and sin is (-1/2)

Answer 5

Correct. So then we would substitute that and have.
\[2(\frac{ \sqrt{3} }{ 2}-i \frac{ 1 }{ 2 })\] Now just multiply the 2 in :3

Answer 6

Ohh okay got it, thank you!! :D

Answer 7

Yep, not that bad :P

Answer 8

Good luck ^_^