is this a correct tree diagram
The Gladstone harbour board decides to issue private boats uusing the Gladstone harbour with 7 digit registration numbers. None of these can start with zero. The harbour board had only been able to get the digits 0, 1, 2, 3, 4, 5, 7, 9 for the boat registration numbers. No digit may be used more than once in each registration number. Bruno, who was responsible for allocating the registration numbers to the boats, had the bright idea of using the number 9 upside down to make 6. However, the 6 and 9 cannot both occur in th same registration number. The registration numbers are issued in ascending orider. Thus the first registration number is 1023567. The next two are 1023576 and 1023679. How many boats can have registration numbers staring with 6.
looks good to me
so there are 5040 outcomes
does it make sense to you?
yes. cool. could u help me with another question. it just gets more difficult . :(
This looks right
fire away
How many boats can have registration numbers staring with 1?
good one... this will be slightly different from the first. you want to give it a shot?
i have got this so far
(7x6x5x4x3x2) - ?
I need to find a way to put 6 without 9 and vice versa
use the inclusion/exclusion principle
how about this... \[\left(\begin{matrix}1 & \alpha & \beta & \gamma & \delta & \epsilon & \eta\\ 1st & 2nd & 3rd & 4th & 5th & 6th & 7th\end{matrix}\right)\] if we exclude 6 and 9, the it will be 6! then we have ot include the 6 and 9 options in all the different spots so we'll have to add to this
can u show me some of the working out i am confused
Do you get the 6! whwne we exclude 6 & 9 from our choices?
I dont know how to do it.
|dw:1376196005325:dw|
9 is also a possibility now
then you'll have 6 spots in which you can include 6 or 9, with 6P5 choices in the remaining 5 spots. so you'll add 6(2*6!) to the previous 6! for a total of 13*6!
6 x 12 = 72
case where a 6 or 9 is chosen + cases where a 6 or 9 isn't chosen
72?
so do i add 6(2*6!)
here is what i have done so far
yes, 12*6! sequences containing 6 or 9 + 6! sequences not including 6 or 9
no, not that picture
i thought there were 7 digits in the registration number...
oh yeah, i am confused would the last one have 6 and 9 on it
is this right?
no, look at this and see if it makes sense...
okay so i should just write up all these and add it together?
yeah, there's 6 spots for the 6 or 9 to go and the 6 & 9 make for 2 choices with 6! for the remaining choices, so that's where the 6*2*6! comes from... get it? then when the 6 and 9 are out of the picture, there's just 6! arrangenments (the first table in the attachement). does this make sense?
okay i will type it up
alright is this right?
yeah, you just have to sum all of those and you should get 13*6!
k
here is what i got
that's it
thanks!
you're welcome
is there a smaller formula i can use a second method i can show
there may be but I don't know what it is
k i know this is asking a lot but can u show me how to find the totla number of possible registration numbers
yeah, it will be in a similar way as we just did the last one. it can't start with 0 right?
yes
okay and it can't have both a 6 and a 9, right?
yes
so do the first table in a similar way where 6 and 9 are excluded and then see how it will change when 6 or 9 is allowed
so should i write out all the tables :O
no, just the first and maybe a couple more to see the pattern
would it not be this: 9360 outcomes x 6 + 5040 outcomes
? where is that coming from?
9360 outcomes comes from the outcomes of starting with 1
yes that
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