5 2/5 ÷ 2 1/4 =
2 2/5
\[5 \frac{2}{5} \div 2 \frac{1}{4}\] \[=\frac{27}{5} \div \frac{9}{4}\] \[=\frac{27}{5} \times \frac{4}{9}\] \[=\frac{3}{5} \times \frac{4}{1}\] \[=\frac{12}{5} = \frac{10 + 2}{5} = \frac{10}{5} + \frac{2}{5} = 2 + \frac{2}{5}\]
For fraction division, invert the fractions then multiply. 5 (2/5) / 2 (1/4) equals (27/5) * (4 / 9) equals 108 / 45 = 2 (18/45) = 2 (2 / 5)
Actually just invert one fraction. (a/b) ÷ (c/d) equals (a/b) × (d/c)
If I did that would I use 27/5 and 9/4 still?
There's more than one way to solve this
\[\left(5 + \frac{2}{5}\right) \times \frac{4}{9}\] \[=\left(5 \times \frac{4}{9}\right) + \left(\frac{2}{5} \times \frac{4}{9}\right)\] \[=\left(\frac{20}{9}\right) + \left(\frac{8}{45}\right)\] \[=\frac{100}{45} + \frac{8}{45}\] \[=\frac{108}{45}\] \[=\frac{90}{45} + \frac{18}{45}\] \[=2+ \frac{2}{5}\]
How does it go from 20 to 100?
If you multiply 20/9 by 5/5 then you get 100/45. You learned in basic math that in order to add fractions the denominator must be the same. We needed to add 20/9 + 8/45
Yes.
I understand now
Thanks!
Personally, I like the second method better. The reason is because I don't like improper fractions.
I was taught with improper fractions so the second one is new to me.
The second method is new to everyone. I sort of invented it.
How do you get the 90/45 and the 18/45? I know if you add them together you get 108 but how do you decide how to do that?
Well, there are two reasons and it beginning with a rule of fractions: \[\frac{c}{d} = \frac{a + b}{d} = \frac{a}{d} + \frac{b}{d}\] In other words, if you had \[\frac{21}{5}\] you can rewrite it as \[\frac{20 + 1}{5}\] Then further re-write it as \[\frac{20}{5} + \frac{1}{5}\] and ultimately \[4 + \frac{1}{5}\] or simply \[4 \frac{1}{5}\] You simplify in this manner to avoid doing side work and show all the steps you did to reduce the problem. I try to produce steps in a manner that shows every step. I don't like using scratch paper to do side work So if I want to reduce 21/5 , I present it in the following manner: \[\frac{21}{5} = \frac{20 + 1}{5} = \frac{20}{5} + \frac{1}{5} = 4 + \frac{1}{5} = 4 \frac{1}{5}\]
Hero - that is an interesting alternative method.
The interesting methods are just the ones that haven't been taught in a classroom. Many students here post alternative methods.
I'm still not understanding where the 90 and 18 come from. Sorry.
It results from thinking ahead. Basically, we know that 108/45 is an improper fraction, so we know it can be reduced to a whole number plus a fraction. 90/45 = 2 because 45 + 45 = 90 and 90 is a multiple of 45, 90 represents the portion of 108 that is divisible by the denominator 45. 18 is what remains since 90 + 18 = 108 Remember we used the addition rule for fractions to rewrite it.
ok
You have to practice it with smaller numbers first in order to understand. Try to reduce \[\frac{13}{3}\] using the same method. Hint: \[\frac{12}{3} = 4\]
so 4 1/3?
Exactly
Because \[\frac{13}{3} = \frac{12 + 1}{3} + \frac{12}{3} + \frac{1}{3} = 4 + \frac{1}{3}\]
Now you can just practice on your own until you get good at it.
Thanks
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