Question

5^(2x+1)=8 Take the common logarithm of both sides of the equation. Use the power property to bring the exponent, (2x + 1), down as a factor. Show your work.

Answer 1

\[\log_b(b^x) = x\]

\[\log_5(5^{2x+1}) = \log_5(8)\]
\[2x + 1 = \log_5(8)\]

simplify for x

Answer 2

(2x +1) * log (5) = log (8)

Answer 3

@Euler271 good answer but you didn't follow the instructions.

Answer 4

Also, log base 5 of 8 isn't all that helpful now that you'll have to change the base :P

Answer 5

(2x+1) = log 8/log5
2x + 1 = 1.2920296742
2x = .2920296742
x = 0.1460148371

Answer 6

Testing the answer
5^(2*0.1460148371+1) = 8

Answer 7

thank you!!!

Answer 8

no problem