5^(2x+1)=8 Take the common logarithm of both sides of the equation. Use the power property to bring the exponent, (2x + 1), down as a factor. Show your work.

Question

5^(2x+1)=8      Take the common logarithm of both sides of the equation. Use the power property to bring the exponent, (2x + 1), down as a factor. Show your work.

anonymous · Answer

$$\log_b(b^x) = x$$

$$\log_5(5^{2x+1}) = \log_5(8)$$
$$2x + 1 = \log_5(8)$$

simplify for x

wolf1728 · Answer

(2x +1) * log (5) = log (8)

agent0smith · Answer

@Euler271 good answer but you didn't follow the instructions.

agent0smith · Answer

Also, log base 5 of 8 isn't all that helpful now that you'll have to change the base :P

wolf1728 · Answer

(2x+1) = log 8/log5
2x + 1 = 1.2920296742
2x = .2920296742
x = 0.1460148371

wolf1728 · Answer

Testing the answer
5^(2*0.1460148371+1) = 8

anonymous · Answer

thank you!!!

wolf1728 · Answer

no problem