Question

The length of a rectangle is twice its width. Let x represent the width of the rectangle.

If the area of the rectangle is 84.5 square centimeters (cm^2), what would be its dimensions?

Answer 1

We know that A=lw, right?

Answer 2

Area=lengthxwidth

Answer 3

yes

Answer 4

And in the problem, the lengh is twice the width. So we could say l=2x. X is the width.

Answer 5

\[84.5^{2} = 2x +x is this the \right the \right expression?\]

Answer 6

Let's start off with seeing what we can pull out of the problem.
The width is x
The length is two times the width, now how can we write that out using the variable?
So we would right it like 2x- So the length is 2x the width is x
Now we are told that the perimeter is 25.5. Now to solve the perimeter we have to add up all 4 sides of the rectangle To get the perimeter.
Now 2x, 2x, x, x, is our equation which we have to solve, so that would give us 6x right?
Change the period into an equal
So it would be 6x =
What number will it equal? According to the problem, What is the perimeter of the rectangle?
It gives us a number
That we can set 6x equal to.
And the number is 25.5, correct?
So now 6x=25.5... now we multiply both sides by 6. So 6 divided by 6=1 and 25.5 divided by 6= 4.25

Answer 7

x = 4.25
[00:17:39] this means the width = 4.25
We are almost done

Answer 8

We now have to solve for length
If x = 4.25
What does 2x equal?

Answer 9

8.5 @Tutor.Stacey

Answer 10

right and that's our answer, nice job!

Answer 11

thank you :)

Answer 12

Width is x Length is 2x. Not a problem!

Answer 13

Does this problem make sense to you now?

Answer 14

im going to try to answer it

Answer 15

Ok, that is great to hear. Good luck with your studies, if you need more help please don't hesitate to ask.

Answer 16

is x= 59.75 the right answer for the width?
then length is 119.5

Answer 17

@Tutor.Stacey ? is x= 59.75 the right answer for the width?
then length is 119.5