Question

Add or subtract as indicated.5x/x+1 + 6/x-1 - 10/x^2-1

Answer 1

@Rowa

Answer 2

to add or substract fractions we must have the same denominator on every fraction

Answer 3

ok

Answer 4

so you understand?

Answer 5

a little my answers are A. 5x - 4 / x +1 B. 5x - 4/ x -1 C. x+1/ x - 1 D . 5x/ x - 1

Answer 6

agent0smith will be able to explain it better

Answer 7

You should start learning to use the equation editor, like this:
\[\Large \frac{ 5x }{ x+1 } + \frac{ 6 }{x-1 }- \frac{ 10 }{x^2 -1 }\]
First step will be to factor the denominator on the far right, the x^2-1... notice it's a difference of two squares. This will help to find the common denominator for all three fractions.

Answer 8

X^2-1 factors to (x+1)(x-1): \[\Large \frac{ 5x }{ (x+1) } + \frac{ 6 }{(x-1) }- \frac{ 10 }{(x+1)(x-1) }\]
Now look at the denominators on the left. What is "missing" from them, that would make the denominator the same as the (x+1)(x-1)?

Answer 9

x^2 - 1 ?

Answer 10

is that right

Answer 11

well.. i don't understand how you got that

Answer 12

but remember, we need to have the same denominator for all fractions to add or substract

Answer 13

Look at (x+1) on the right. What is missing from that, that'd make it the same as (x+1)(x-1)?

compare the two:
(x+1)
(x+1)(x-1)

what's missing from the first?

Answer 14

(x - 1)

Answer 15

Good. So now we have to multiply both the numerator and denominator of it like so: \[\Large \frac{ 5x (x-1) }{ (x+1) (x-1)} + \frac{ 6 }{(x-1) }- \frac{ 10 }{(x+1)(x-1) }\]

Now what's missing from the middle fractions denominator, x-1, that'll make it the same as the other two?

Answer 16

(x+1)

Answer 17

Good. \[\Large \frac{ 5x (x-1) }{ (x+1) (x-1)} + \frac{ 6(x+1) }{(x+1)(x-1) }- \frac{ 10 }{(x+1)(x-1) }\]
Now you can add it all together over the common denominator, (x+1)(x-1). And simplify the numerators of those two fractions, by distributing.

Answer 18

i add 5x(x-1) + 6 ( x +1) - 10?

Answer 19

Yes. But you have to distribute first.

So you have \[\Large \frac{ 5x (x-1) + 6(x+1) - 10 }{ (x+1) (x-1)} \]

Answer 20

could you break that down as well

Answer 21

Just simplify the top. I gotta go, good luck finishing, from here it's easy! :)

Answer 22

ok thank you !!

Answer 23

@Rowa i got 5x-4/x+1 am i correct?

Answer 24

i think 5x-4/x-1

Answer 25

double check it to make sure

Answer 26

ok thank you could you help me with another

Answer 27

wish i could, but i have exams in a few days

Answer 28

ok thanks anyways

Answer 29

no problem ;)

Answer 30

5x-4/x-1 - That is correct. Make sure you use parentheses, though... (5x-4)/(x-1)